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Work & Energy 05 |
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OPENING QUESTIONS:
Write a sketch and do a full wolgemuthian response/analysis
Now give your sheet to the person at your next clockwise position: 1) Give that person 1 point for an appropriate sketch with all parts labeled correctly (gravity, normal force, spring force, friction) 2) Give 1 point for some indication that ∑Fx = max = 0 4) Give 1 point for somewhere indicating that the restoring force of the spring is equal (or less than) the friction force of the block. 5) Give 1 point for showing appropriate substitutions 6) Give 1 point for showing appropriate sig figs: 7) I don't care about the answer...(but I got μ = (-k)(x)/(m)(g) = .77 (2 sig figs) For those of you who whipped through this to find the answer, please note, the answer is the LEAST important part of the problem... really... honest.... get used to it. ═══════════════════════════ LEARNING OBJECTIVES: 1) I will be able to use the concept of gravitational potential energy to solve basic energy equations after today's class. WORDS O' THE DAY:
FORMULAE OBJECTUS:
A change and/or transfer of energy requires WORK, or to put it perhaps a bit more succinctly, WORK is defined as a transfer of ENERGY WORK O' THE DAY: Let's take a moment to revisit the spring-between-two-blocks part of last Friday's homework. The question really boils down to.... what? Also, let's take a gander at why it is so helpful (AND expedient!!) to solve problems using the isolate/substitute/solve model. ═══════════════════════════ Recall from the previous unit that the Newton's Second is often written quantitatively as F = ma. Also note that from last week we learned that the energy exerted on a spring (to compress it) or by a spring (as it decompresses) is Hooke's Law: F = -kx Is the "F" in each equation the same sort of F. In otherwords, can we substitute one equation in for the other on an "as needed" sorta basis? ═══════════════════════════ ANSWER: YES... force is force is force... One of the things that often befuddles Newbies in physics is the seemingly ad hoc way that we sometimes substitute one equation for another. Get used to that. One of the keys to understanding physics is to 'cross over' from one application (for example Newton's Laws (dynamics) with the motion of a spring (as shown by Hooke's Law) or even gravitational attraction or rotational dynamics. The important thing to keep track of is that there are certain equations that will weave their way in and out of our conversations of physics. If I were you, I'd have a special page in my notes that says something like: HERE BE THE GONZO EQUATIONS OF PHYSICS:
NEW STUFF Potential Energy is defined to exist when a system exists where energy can be stored. Discuss with your groups please...Give an everyday example where energy is stored...
═══════════════════════════ Energy can be stored in:
Now let's consider the last example: How is the POTENTIAL energy of the water stored behind a damn converted into actual energy for us when we plug in our microwave to burn popcorn (electrical energy) Of particular interest to us in this unit is GRAVITATIONAL POTENTIAL ENERGY... Let's have someone come up and lead our conversation.... Energy created in this fashion is fairly cheap to produce (unless of course you're a salmon, but that's another story), and very plentiful inthe Northwest. Take a look at the Grand Coulee Power Plant:
The falling water (converted from Gravitational Potential Energy of the water just sitting behind the damn into kinetic energy of falling water) spins the blades of the turbine (and as we'll see next semester) transfers that kinetic energy into electric energy that then flows down the wires to our homes. If you're interested, here are the specs. Those turbines generate 6800 million watts of energy (we'll talk about watts very soon, but for now think of a watt as Nm/sec or Joules/sec) As a general rule of thumb, one megawatt (1 million watts) is enough energy to power about 2500 average American homes. ═══════════════════════════ ANYWHO..... Gravitational Potential Energy is found very easily by the following equation: Ug = mgy I HAVE NO IDEA who came up with "U" to describe potential energy, but we're stuck with it, so add it to your GONZO list. Not surprisingly (I hope) When the only work done on or by a system involves potential energy, the change in potential energy of an object in that system is given as: W = mgyf - mgyi where y is the change in the displacement of the object in meters or, more succinctly: W = ∆U Take a gander at the equation 7.8 on page 193.
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